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Python使用Flask框架同时上传多个文件的方法

PHP admin 11个月前 (05-31) 8次浏览 0个评论
本文实例讲述了Python使用Flask框架同时上传多个文件的方法,分享给大家供大家参考。具体如下:

下面的演示代码带有详细的html页面和python代码

import os
# We'll render HTML templates and access data sent by POST
# using the request object from flask. Redirect and url_for
# will be used to redirect the user once the upload is done
# and send_from_directory will help us to send/show on the
# browser the file that the user just uploaded
from flask import Flask, render_template, request, redirect, url_for, send_from_directory
from werkzeug import secure_filename
# Initialize the Flask application
app = Flask(__name__)
# This is the path to the upload directory
app.config['UPLOAD_FOLDER'] = 'uploads/'
# These are the extension that we are accepting to be uploaded
app.config['ALLOWED_EXTENSIONS'] = set(['txt', 'pdf', 'png', 'jpg', 'jpeg', 'gif'])
# For a given file, return whether it's an allowed type or not
def allowed_file(filename):
  return '.' in filename and 
      filename.rsplit('.', 1)[1] in app.config['ALLOWED_EXTENSIONS']
# This route will show a form to perform an AJAX request
# jQuery is loaded to execute the request and update the
# value of the operation
@app.route('/')
def index():
  return render_template('index.html')
# Route that will process the file upload
@app.route('/upload', methods=['POST'])
def upload():
  # Get the name of the uploaded files
  uploaded_files = request.files.getlist("file[]")
  filenames = []
  for file in uploaded_files:
    # Check if the file is one of the allowed types/extensions
    if file and allowed_file(file.filename):
      # Make the filename safe, remove unsupported chars
      filename = secure_filename(file.filename)
      # Move the file form the temporal folder to the upload
      # folder we setup
      file.save(os.path.join(app.config['UPLOAD_FOLDER'],filename))
      # Save the filename into a list, we'll use it later
      filenames.append(filename)
      # Redirect the user to the uploaded_file route, which
      # will basicaly show on the browser the uploaded file
  # Load an html page with a link to each uploaded file
  return render_template('upload.html', filenames=filenames)
 
# This route is expecting a parameter containing the name
# of a file. Then it will locate that file on the upload
# directory and show it on the browser, so if the user uploads
# an image, that image is going to be show after the upload
@app.route('/uploads/')
def uploaded_file(filename):
  return send_from_directory(app.config['UPLOAD_FOLDER'],
                filename)
if __name__ == '__main__':
  app.run(
    host="0.0.0.0",
    port=int("80"),
    debug=True
  )

index.html代码



 
  
 
 
  

How To Upload a File.


upload.html页面:



 
  
 
 
  

Uploaded files


This is a list of the files you just uploaded, click on them to load/download them

    {% for file in filenames %}

  • {{file}}
  • {% endfor %}

Code to manage a Upload


@app.route('/upload', methods=['POST'])
def upload():
  # Get the name of the uploaded file
  #file = request.files['file']
  uploaded_files = request.files.getlist("file[]")
  filenames = []
  for file in uploaded_files:
    # Check if the file is one of the allowed types/extensions
    if file and allowed_file(file.filename):
      # Make the filename safe, remove unsupported chars
      filename = secure_filename(file.filename)
      # Move the file form the temporal folder to the upload
      # folder we setup
      file.save(os.path.join(app.config['UPLOAD_FOLDER'], filename))
      filenames.append(filename)
      # Redirect the user to the uploaded_file route, which
      # will basicaly show on the browser the uploaded file
  # Load an html page with a link to each uploaded file
  return render_template('upload.html', filenames=filenames)

希望本文所述对大家的Python程序设计有所帮助。


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